Find hcf and lcm of 120 and 140 by using fundamental theorem of arithmetic

20 and 4200

Step-by-step explanation:

Express the numbers as products of their prime factors.

120 = 2 × 2 × 2 × 3 × 5

140 = 2 × 2 × 5 × 7

Identify the prime factors that both numbers have in common and multiply them.

both have 2, 2 and 5, thus

HCF = 2 × 2 × 5 = 20

Multiply each factor the greatest number of times it occurs in either number.

2 : 3 times

3 : 1 time

5 : 2 times

7 : 1 time

LCM = 2 × 2 × 2 × 3 × 5 × 5 × 7 = 4200

HCF = 20

LCM = 840

Step-by-step explanation:

120 = 2×2×2×3×5

140 = 2×2×5×7

HCF: 2×2×5 = 20

LCM: 140×2×3 = 840

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles