A number m is such that when it is divided by 30,36 and 45 ,the remainder is always 7.Find the smallest possible value of m

hello there

i hope this answer will help you :)

Step-by-step explanation:

Suppose that you are looking for b, instead of the irrelevant value of m

The statements of this problem suggest us to look for the Least Common Multiple (LCM) of 30, 36 and 45

The number b will be that LCM + 7.

Hence,

30 = 2 x 3 x 5

36 = 2^2 x 3^2

45 = 3^2 x 5

LCM = 180

Therefore the smallest possible value of b (or ‘m’ as per question) is -> LCM+7 that is 180+7= 187

rick would give her the best deal as he will charge $8.88 per hour