Through: (-5, -5), slope=2/5

y = 2/5x - 3

Step-by-step explanation:

I guess the question should be: find the equation of a line that passes through a point

(-5 , -5) with a slope of 2/5.

Step 1: find the slope

We are given slope to be 2/5

m = 2/5

Step 2: substitute m into the equation of a line

y = mx + c

y = 2/5x+ c

Step 3: substitute the point into the equation

( -5 , -5)

x = -5

y = -5

y = 2/5x+ c

-5 = 2/5(-5) + c

-5 = 2 * -5/5 + c

-5 = -10/5 + c

-5 = -2 + c

-5 + 2 = c

-3 = c

c = -3

Substitute c = -3

y = 2/5x + c

y = 2/5x - 3

so, converting firstly the mixed fractions to improper fractions and then "adding".

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step-by-step explanation: