Each of 10 bins contain 1 piece of fruit. Two bins are oranges, 3 are apples, 4 are peaches, and 1 is a melon. What is the probability that you didn't choose two peaches

Step-by-step explanation:

Here, the total number of bins  = 10

Total orange bins  = 2

Total apples bins  = 3

Total peaches bins  = 4

Total melon bins  = 1

Let E : Event of picking two peaches

So, P(Picking 1 peach )  =

and P (Picking 2nd  peach )  =

So, the probability of not picking 2 peaches  = 1 - P(picking  2 peaches)

Hence, the probability of not choosing 2 peaches is .

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step-by-step explanation:

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1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.