Let f(x)=x2+15x+56
What are the zeros of the function?

Enter your answers in the boxes

and

-8, -7

Step-by-step explanation:

f(x)=x^2+15x+56

0 =x^2+15x+56

What two numbers multiply together to make 56 and add together to 15

7*8 = 56

7+8=15

0 = (x+8) (x+7)

Then use the zero product property

x+8 =0     x+7 =0

x+8-8 =0-8        x+7-7 =0-7

x=-8                      x=-7

-7 , -8

Step-by-step explanation:

x² + 15x + 56 = 0

x² + 7x + 8x + 56 = 0

x(x + 7) + 8(x + 7) = 0

(x + 7)(x + 8) = 0

x = -7 , -8

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

the correct answer is 5 6 and 7