What is the interquartile range of the data? With the numbers 2,3,3,4,5,7,8,8,8,10,10, and 12

The interquartile range = 5.5

Step-by-step explanation:

Given the data

2   3   3   4   5   7   8   8   8   10   10   12

As we know that

The interquartile range is the difference between the third and first quartiles.

So, to find the first quartile, we need to place the numbers in value order and find the bottom half.

2   3   3   4   5   7   8   8   8   10   10   12  

So, the bottom half is

2   3   3   4   5   7  

The median of these numbers is 3.5.

So, to find the third quartile, we need to place the numbers in value order and find the upper half.

2   3   3   4   5   7   8   8   8   10   10   12  

So, the upper half is

8   8   8   10   10   12  

The median of these numbers is 9

so

The third quartile is 9.

The first quartile is 3.5.

The interquartile range is the difference between the third and first quartiles.

The interquartile range = 9 - 3.5 = 5.5

Therefore, the interquartile range = 5.5

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2