A right pyramid with a square base has a base edge length of 12 meters and slant height of 6StartRoot 2 EndRoot meters. The apothem is meters. The hypotenuse of ΔABC is the . The height is meters. The volume of the pyramid is cubic meters.

Volume of the right pyramid = 288 m²

Step-by-step explanation:

Volume of the pyramid =

From the ΔAOB,

By Pythagoras theorem,

AB² = AO² + OB²

(6√2)² = AO² + (6)²

72 = AO² + 36

AO = √(36) = 6 m

Since base of the pyramid is a square so area of the base = (Length × Width) = (side)²

Now volume of the pyramid =

                                               =

                                               = 288 m²

Therefore, volume of the right pyramid is 288 m².

The answer would be b ! explanation: the formula for sa *surface area * is 2×l×w+2×l×h+2×w×h so in this case l=4w=12h=8so you use the formula to solve it and it give you the answer of 352^cm^2

Dcups i think