At the beginning of the day, stock XYZ opened at $3.72. At the end of the day,
it closed at $4.05. What is the rate of change of stock XYZ?
O A. 8.1%
O B. 13.3%
O. C. 8.9%
O D. 33.0%
SUBMIT

Solve for the difference between the price of the stocks at the beginning of the day and at the end. 

                                     d = $4.05 - $3.72 = $0.33

Divide this value by the original value of the stocks and multiply by 100% to get the rate of change.

                      ($0.33 / $3.72) x 100% = 8.87%

Thus, the answer is letter A. 8.9%. 

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.