There are two noncongruent triangles where B - 55°, a = 15, and b = 13. Find the measures of the angles of the triangle with the
greater perimeter. Round to the nearest tenth if necessary.

I tried to use the law of consines

Step-by-step explanation:

b^2 = a^2 + c^2 - 2ac*cos(B)

13^2 = 15^2 + c^2 - 2*15*c*cos(55)

169 = 225 + c^2 - 30c*cos(55)

c^2 - 30c*cos(55) + 225 - 169 = 0

c^2 - 30c*cos(55) + 56 = 0

c = (30*cos(55) +/- sqrt((30*cos(55))^2 - 4*1*56)) / (2*1)

c = (30*cos(55) +/- sqrt(900*cos^2(55) - 224)) / 2

c = 15*cos(55) +/- sqrt(225*cos^2(55) - 56)

To have the greater perimeter we want the larger value of c:

c = 15*cos(55) + sqrt(225*cos^2(55) - 56)

c =~ 12.848965599926043766708967572196

010

:

step-by-step explanation:

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step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35