Mathematics, 21.03.2020 11:41 kloeydrea08

Jacob does the long jump for his track team. On his first jump, he jumped 7
2
3
feet. His second jump was 1
1
3
feet shorter. How far was Jacob's second jump?
A) 5
1
2
feet
B) 6
1
3
feet
C) 6 feet
D) 7
1
3
feet

Answers: 3

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Answers

Answer from: pamelperezz26

Jacob's second jump was 6 1/3 feet

Step-by-step explanation:

On his first jump, he jumped 7 2/3

feet. We would convert each mixed fraction to improper fraction

to enable easy addition and subtraction. Converting 7 2/3 feet to improper fraction, it becomes 23/3 feet.

His second jump was 1 1/3 feet shorter. Converting 1 1/3 feet to improper fraction, it becomes 4/3 feet.

Therefore, the distance that Jacob covered on his second jump would be

23/3 - 4/3 = 19/3 feet

Converting 19/3 feet back to mixed fraction, it becomes

6 1/3 feet

Answer from: Quest

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

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answers

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step-by-step explanation:

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

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Jacob does the long jump for his track team. On his first jump, he jumped 7
2
3
fe...

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