A tree harvester estimates the trunk of a tree to have a height of about 38 meters and a base diameter of about 0.62 meter. The wood of the tree has a density of about 520 kilograms per cubic meter. Find the mass of the trunk. Round your answer to the nearest hundred.

Mass of trunk = 6100 kg

Step-by-step explanation:

The trunk of the tree is cylindrical. We would apply the formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

h represents the height of the cylinder.

r represents the radius of the cylinder.

π is a constant whose value is 3.14

From the information given

Height = 38 meters

Diameter of circular base = 0.62 meters.

Radius = diameter/2 = 0.62/2 = 0.31 meters

Therefore,

Volume of trunk = 3.14 × 0.31² × 38 =

11.47 m³

Mass = density × volume

Mass of the trunk = 520 kilograms per cubic meter

Mass of trunk = 520 × 11.47 = 6056.16 kg

Rounding to the nearest hundred,

Mass of trunk = 6100kg

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9