Circle W has diameter endpoints (- 10, 6) ) and (2, - 8) . What is the equation of the circle W in standard form?

The equation of circle W in standard form is + = 85

Step-by-step explanation:

Given the diameter endpoints: (-10,6) and (2, -8)

We know that the equation of circle is given by

+ =

where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.

To find (h,k): the center is midpoint of diameter

Midpoint of diameter with end points (x1,y1) and (x2,y2) is given by

( ,  )

(  ,  )

(-4,-1)

Hence (h.k) is ( -4,-1)

Substituting values of (h.k) and (x.y) as (-4,-1) and (2,-8) respectively in equation of circle, we get

+=

= 85

Substituting the values of (h,k) and , we get the equation of circle as

+ = 85

Hence the equation of circle W in standard form is + = 85

angle addition postulate

2x=56

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°