A confidence interval estimate is desired for the true mean gain in a circuit on a semiconductor device. Assume that the gain is normally distributed with a standard deviation How large must n be if the length of the 95% CI on is to be 10

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)