Assume that a sample is used to estimate a population proportion p. Find the margin of error M. E. that corresponds to a sample of size 329 with 49 successes at a confidence level of 99.5%.

The magin of error is 0.0552 = 5.52 percentage points.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error is:

For this problem, we have that:

99.5% confidence level

So , z is the value of Z that has a pvalue of , so .

M.E:

The magin of error is 0.0552 = 5.52 percentage points.

2nd one in the first row is correct

8/k

step-by-step explanation: