Find the area of an octagon with a side length of 6

173.82 cm^2 to the nearest hundredth.

Step-by-step explanation:

We can split it up into 8 isosceles triangles of equal area.

The base of one of these triangles = 5 cm in length.

The vertex angle is 360 / 8 = 45 degrees.

We can draw a perpendicular line from the center to form  2 right angled triangles and the 45 degree angle is split into 2 angles of 22.5 degrees and the base of these triangles is 1/2 * 6 = 3 cm.

The height of an isosceles triangle is found as follows:

tan 22.5 = 3 / h

h = 3 / tan 22.5

So the area of the isosceles triangle =   (3 * 3 / tan 22.5) cm^2.

Total area of the octagon = 8 * 3 * 3 / tan 22.5

= 173.82 cm^2.

eve and marks ratios are equivalent

step-by-step explanation: