Enter an equation to find three numbers with the following properties. Let x be the first number. The second number is 6 more than the first number. The third number is 7 times the second number. The sum of the third number and the product of the first and second numbers is 0. Solve the equation and give the three numbers.

-7, -1, -7

-6, 0, 0

Step-by-step explanation:

x

x+6

7(x+6)

7(x+6)+ x(x+6) = 0

(x+6)(7+x) = 0

x = -6, -7

-6, 0, 0

-7, -1, -7

First number: x

Second number: (x + 6)

Third number: (x + 6) * 7

Equation: 0 = (x)(x + 6) + 7(x + 6)

Steps to solve:

0 = x^2 + 6x + 7x + 42

0 = x^2 + 13x + 42

Using the quadratic equation, x could equal -7 or -6. In our equation above, both are applicable.

The three numbers could be -6, 0, and 0. Or they could be -7, -1, and -7.

Hope this helps!! :)

ddsf

step-by-step explanation:

dfs

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.