A postcard has an area of 24 square inches. Two enlargements of the postcard have areas of 54 square inches and 96 square inches. In each postcard, the length is 1 and 1/2 times the width. What could be the dimensions of the postcard or the enlargements.

Step-by-step explanation:

Given:

Initial area, Ai = 24 in^2

First enlargement, A1 = 54 in^2

Second enlargement, A2 = 96 in^2

Length, L = 3/2 × B

Area of a rectangle = L × B

Ai = 3/2B × B

24 = 3/2 B^2

B = sqrt(16)

= 4 in

A1 = 3/2B × B

54 = 3/2 B^2

B = sqrt(36)

= 6 in

A2 = 3/2B × B

96 = 3/2 B^2

B = sqrt(64)

= 8 in

For the first enlargement,

2in : 3in

Second enlargement,

1in : 4in

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

heudhduxhdnshenebdutbbt

step-by-step explanation:

hrhhdhdbbrurb ees