Solve using the quadratic formula x2 - 6x - 40=0 Question options: x = 10 or x = -4 x = 4 or x = -10 x = -7 or x = 7 x = -4 - √7 or x = -4 + √7

Step-by-step explanation:

The given quadratic equation is expressed as

x² - 6x - 40 = 0

The equation is already in the standard form of ax² + bx + c

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 1

b = - 6

c = - 40

Therefore,

x = [- - 6 ± √(- 6² - 4 × 1 × - 40)]/2 × 1

x = [- 6 ± √(36 - - 160)]/2

x = [- 6 ± √196]/2

x = (- 6 + 14)/2 or x = (- 6 - 14)/2

x = 8/2 or x = - 20/2

x = 4 or x = - 10

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

it would be 3 ÷by 6 because the number on each side