Junior has saved money in his piggybank over the winter. He wants to buy a $30 computer game. If he has 14 one-dollar bills, 16 half dollars, 12 quarters, 8 dimes, 25 nickels, and 10 pennies, how much more does he need to borrow from Dad to buy the game?

Step-by-step explanation:

The worth of a dime is 10 cents. Converting to dollars, it becomes

10/100 = $0.1

8 dimes = 8 × 0.1 = $0.8

The worth of a penny is 1 cent. Converting to dollars, it becomes

1/100 = $0.01

10 pennies = 10 × 0.01 = $0.1

The worth of a nickel is 5 cent. Converting to dollars, it becomes

5/100 = $0.05

25 nickels = 25 × 0.05 = $1.25

The worth of a quarter is 25 cent. Converting to dollars, it becomes

25/100 = $0.25

12 quarters = 12 × 0.25 = $3

16 half dollars = 16 × 0.5 = $8

14 one-dollar = 14 × 1 = $14

The total amount of money that he has is

14 + 8 + 3 + 1.25 + 0.1 + 0.8 = $27.15

Since he wants to buy a $30 computer game, then the additional amount that he needs to borrow from her dad is

30 - 27.15 = $ 2.85

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.