Onsider the binomial distribution with n trials and P(S) = p. (a) Show that p(y) p(y − 1) = (n − y + 1)p yq for y = 1, 2, , n. Equivalently, for y = 1, 2, , n, the equation p(y) = (n − y + 1) p yq p(y − 1) gives a recursive relationship between the probabilities associated with successive values of Y.

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This is what i found “an explicit formula designates the nth term of the sequence, as an expression of n (where n = the term's location). it defines the sequence as a formula in terms of n. this example is an arithmetic sequence(the same number, 5, is added to each term to get to the next term).” i hope this you for what your looking for. can you plz mark me brainliest?