The absorbance of the solution at 710nm increases so that it off the scale of the spectrophotometer (values > 2). To correct for these values, we must adjust the absorbances so that the correct values can be calculated. To do so a ratio of the highest accurate absorabance can be used to determine the extinction coefficent of 710 nm. Solve for this value based on absorbances using tube 6.

here is your mark brainliest

alright so i think for this one it would to draw it out. this may be hard for me to try and draw, but i will do my best on here:

        r

  /       |     \

notice how it forms 2 triangles inside one bigger triangle.

so if we know the angle spr is the same as psr that is saying the measure of angle p is the same as angle s. this means the big triangle psr is either isosceles or equilateral. in both cases, the triangle is perfectly symmetrical when split down the middle, which is in this case rq. because we know it is perfectly symmetrical on both sides, we know that the two triangles inside the bigger one are equal.