The sum of three consecutive intergers is 267. What is the largest integer

90

Step-by-step explanation:

Let the starting number be x, the two consecutive numbers after x is gonna be x+1 and x+2.

If the sum of these three numbers is 267 then:

x+(x+1)+(x+2)=267

Solve

3x+3=267

3x=267-3

3x=264

x=264/3

x=88

x+1=89

x+2=90

Your three consecutive numbers are 88, 89, and 90.

The largest one of them is 90.

88+89+90=267

Step-by-step explanation:

To do this just divide 267/3 and you get 89, you just look for the previous number (88) and the top number (90) and the sums.

88.89.90

so, converting firstly the mixed fractions to improper fractions and then "adding".