A certain television is advertised as a 26 inch TV (the diagonal length). If the width of the TV is 10 inches, how many inches tall is a TV?

The TV is 24 inches tall

Step-by-step explanation: The question has provided the diagonal and the width of the rectangle shaped television. From this bit of information, we can deduce that the diagonal of the rectangle (television) is also the Hypotenuse (26 inches) while the the other two sides are the Length and the Width (10 inches).

For every right angled triangle, we can apply the Pythagoras theorem to solve for any unknown side. The theorem states that

AC² = BC² + AB²

Where AC is the hypotenuse (longest side)

26² = 10² + AB²

676 = 100 + AB²

Subtract 100 from both sides of the equation

576 = AB²

Add the square root sign to both sides of the equation

√576 = √AB²

24 = AB

Therefore, the height of the television is 24 inches

add an !

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3