A force of 360 newtons stretches a spring 2 meters. A mass of 20 kilograms is attached to the end of the spring and released from the equilibrium position with an upward velocity of 5 meters per second. Find the equation of motion.

Step-by-step explanation:

The statement of the problem shows a case of simple harmonic movement, whose expressions for position is:

An expression for velocity is found by deriving the previous one:

The angular frequency is:

Amplitude and phase angle are found by replacing and simplifying motion formulas:

The equation of motion is:

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh