If the discriminant equals 0, then the quadratic has:

a. 1 Real Solution

b. No Real Solutions

c. 2 Real Solutions

1

Step-by-step explanation:

haha idk why, thats te answer but i remember the rule

if its less that 0, than theres no solutions

if its more than 0, then i can be multiple

if its 0, its 1 solution

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

english, cause i can’t you