Does the point (2√3, 2) lie on the circle that is centered at the origin and contains the point (0, -4)? Explain?

The answer to your question is Yes, the point P lies on the circle

Step-by-step explanation:

Data

P (2, 2)

Center (0, 0)

Q (0, -4)

Process

1.- Find the radius of the circle

dCQ =

dCQ =

dCQ =

dCQ = 4

2.- Find the equation of the circle

    (x - 0)² + (y - 0)² = 4²

-Simplification

           x² + y² = 16

3.- Substitute P in the equation of the circle

          (2)² + (2)² = 16

           4(3) + 4 = 16

               12 + 4 = 16

                     16 = 16

4.- Conclusion

The point (2, 2) lies on the circle because when we evaluate the equation of the circle with this point, we get the length of the radius.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.