Your bill at a restaurant is $4.65, and you decide to tip the waitress 90e. Because

you have only 20e in nickels, you give her six dollar bills and ask for change. The

waitress has only two quarters in change. Without changing your plans, how do

you solve this problem?

I will give her $6.05 and collect the $0.5 in her possession

Step-by-step explanation:

Before proceeding, we need to know the quantity or equivalent of some of the things mentioned.

a.Nickel:- a nickel is 5¢, this means that the 20¢ in nickels that you had in your possession while in the restaurant is equal to (20/5) 4 nickel coins.

b. Two quarters :- Just as the name implies; 2 quarters of a dollar is [(1/4) + (1/4)] of 1 dollar = 50 cent.

We need to calculate the entire amount that needs to be given to the waitress. Since your bill after eating at the restaurant is $4.65 and the intended tip is 90¢, the sum that should be offered to her =

$4.65 + $0.90

= $5.55 (five dollars : fifty five cent).

According to the question, you have only 20 cents in nickels, so although you have five dollar bills to give the waitress, 55¢ is not available. Again, if you offer her six dollar bills, she wouldn't be able to give you a change of 45¢ ($6.00 - $5.55) because she only has 2 quarters of a dollar (50¢).

Now, since you are in possession of 20¢ in nickels, the best way to tackle the situation is to demand the two quarters that she has while handing out the 6 dollar bills and 1 nickel (5¢) to her. So, you should simply offer her $6.05 while you collect $0.50 from her in return)

Recall that the total amount that must be given to her (bill + tip) = $5.55

Then subtracting 50¢ from $6.50¢ will give:

$6.05 - $0.50

= $5.55

Therefore you have given her exactly $5.55¢ if you offer her six dollars five cent and collect fifty cents in return.

c

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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