A gardener is planting two types of trees: Type A is 3 feet tall and grows at the rate of 13 inches per year. Type B is 10 feet tall and grows at a rate of 6 inches per year. Algebraically determine exactly how many years it will take for these trees to be the same height.

Solution:

Let "x" be the number of years

Type A is 3 feet tall and grows at the rate of 13 inches per year

1 feet = 12 inches

3 feet = 3 x 12 = 36 inches

Equation: 36 + 13x eqn 1

Type B is 10 feet tall and grows at a rate of 6 inches per year

10 feet = 120 inches

Equation: 120 + 6x eqn 2

For both trees to be of same height, eqn 1 must be equal to eqn 2

36 + 13x = 120 + 6x

13x - 6x = 120 - 36

7x = 84

x = 12

Thus it takes 12 years for both trees to be of same height

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;