The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 265 people entered the park, and the admission fees collected totaled 760.00 dollars. How many children and how many adults were admitted?

Your answer is

120 children and 145 adults were admitted

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of children admitted.

y is the number of adults admitted.

265 people entered the park

This means that

The admission fee at an amusement park is $1.50 for children and $4 for adults. The admission fees collected totaled 760.00 dollars.

This means that

So

From the first equation:

Replacing in the second equation:

120 children and 145 adults were admitted

120 children and 145 adults were admitted that day.

Step-by-step explanation:

Let x represent the number of children that were admitted that day.

Let y represent the number of adults that were admitted that day.

On a certain day, 265 people entered the park. it means that

x + y = 265

The admission fee at an amusement park is $1.50 for children and $4 for adults. On that day, the admission fees collected totaled 760.00 dollars. This means that

1.5x + 4y = 760- - -- - - - - - - - -- -1

Substituting x = 265 - y into equation 1, it becomes

1.5(265 - y) + 4y = 760

397.5 - 1.5y + 4y = 760

- 1.5y + 4y = 760 - 397.5

2.5y = 362.5

y = 362.5/2.5

y = 145

x = 265 - y = 265 - 145

x = 120

inequality:

620-37.4p ≥ 450

the minimum amount of packages needed to be removed from the elevator is 5.

step-by-step explanation: