The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70 cm cubed of water. Find the percent of the cup that is filled with water after 3 seconds.

In 3 seconds the cup is filled with .

Step-by-step explanation:

Given:

2 seconds = water

We need to find the percent of the cup that is filled with water after 3 seconds.

Solution:

Now Given:

The cup was filled at a constant rate.

First we will find the volume of water filled in the cup after 1 seconds.

2 seconds = water

1 seconds = Volume of water filled in 1 second.

By Using Unitary method we get;

Volume of water filled in 1 second =

Now we will find the volume of water filled in the cup after 3 seconds.

1 second = of water is filled

3 seconds = volume of water filled in the cup after 3 seconds

Again by using Unitary method we get;

volume of water filled in the cup after 3 seconds =

Hence In 3 seconds the cup is filled with .

To find the percent of the cup filled with water after 3 seconds we would required the dimensions of the cup which is not available in the question.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

the answer is b