If the lesser of the two consecutive even integers is five more than half the greater, what are the two integers?

The integers are 12, 14.

Solution:

Let the even consecutive integers be x and x + 2.

Lesser number = x and Greater number = x + 2

Lesser number = Half of greater number + 5

To add the numbers, denominators must be same. So multiply 5 by .

Multiply by 2 on both sides, we get

⇒ 2x = x + 12

Subtract x from both sides.

⇒ x = 12

Lesser number = 12

Greater number = 12 + 2 = 14

Hence the integers are 12, 14.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option