An opaque bag contains 3 green marbles, 3 red marbles. If two consecutive marbles are drawn without replacement what is the probability that they will both be green?

~ 5/6 ~

Step-by-step explanation:

3 green (1/2)

3 red (1/2)

Total is 6

The first time is 1/2 green.

The second time, since we took one away without putting it back, 1/3 green.

Then, you have to add them together.

Change them first, though.

1/2 changes to 3/6.

1/3 changes to 2/6.

3/6 + 2/6 = 5/6

We can not simplify it, so 5/6 is the end result.

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

based on context clues you gave i'm assuming the answer would be c.