If measure angle MPL=63 HOW COULD I FIND THE OTHERS?

JK = 27

NJ = 153

JL = 117

KNM = N/A

MJL = N/A

JLK = N/A

step-by-step explanation:

∠NPM + ∠MPL = 90

∠NPM + 63 = 90

∠NPM = 27°

so, ∠JPK = 27° (since they are vertical angles)

63 + 90 + 27 + 27 + X = 360

63 + 90 + 27 + 27 + X = 360

207 + X = 360

X = 153

so, ∠JPN = 153°

ARCS:

JK = 27

NJ = 153

JL = 117

KNM = N/A

MJL = N/A

JLK = N/A

- sorry this is the furthest i can help, i have only learnt up to that so do not know how to find the rest.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

i think it is 18

step-by-step explanation: