Use synthetic substitution to find f(­2) and f(3).

1.f(x) = 3x^4 ­- 12x^3 ­- 12x^2 + 30x

2. Write the polynomial equation of degree 4 with leading coefficient 1 that has roots at ­-2, ­-1, 3, and 4.

see explanation

Step-by-step explanation:

(1)

To obtain f(2) and f(3) substitute x = 2, x = 3 into f(x)

f(2) = 3( ) - 12(2³) - 12(2²) + 30(2)

      = 48 - 96 - 48 + 60 = - 36

f(3) = 3( ) - 12(3³) - 12(3²) + 30(3)

      = 243 - 324 - 108 + 90 = - 99

(2)

Given a polynomial with roots x  = a, x = b, then

(x - a), (x - b) are the factors

and the polynomial is the product of the factors

Here the roots are x = - 2, x = - 1, x = 3 and x = 4, thus the factors are

(x + 2), (x + 1), (x - 3) and (x - 4)

The polynomial is the product of the factors, thus

f(x) = (x + 2)(x + 1)(x - 3)(x - 4) ← expand in pairs using FOIL

     = (x² + 3x + 2)(x² - 7x + 12) ← distribute

     = - 7x³ + 12x² + 3x³ - 21x² + 36x + 2x² - 14x + 24 ← collect like terms

     = - 4x³ - 7x² + 22x + 24

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

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