Write the point-slope form of the line's equation satisfying the given conditions. Then use the point-slope form of the equation to write the slope-intercept form of the equation. Slopeequals4, passing through (6,7)

y - 7 = 4(x - 6)

y - 7 = 4x - 24

y = 4x - 24 + 7

y = 4x - 17

Step-by-step explanation:

The point slope form is expressed as

y - y1 = m(x - x1)

Where

m represents slope of the line

y1 represents initial value of y

x1 represents initial value of x

The given line has a slope of 4 and passes through (6, 7)

y1 = 7

x1 = 6

Therefore, the equation becomes

y - 7 = 4(x - 6)

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c represents the y intercept.

From the point slope form,

y - 7 = 4x - 24

y = 4x - 24 + 7

y = 4x - 17

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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step-by-step explanation: vsfdvsfvd