You are dealt two cards successively without replacement from a standard deck of 52 playing cards. Find the probability that the first card is a two and the second card is a ten. Round your answer to three decimal places. A. 0.250 B. 0.994 C. 0.500 D. 0.006 Click to select your answer.

(D) 0.006

Step-by-step explanation:

Total number of cards :52

Please note that, all cards have a the possibility of appearing 4 times.

Hence total possible number of a '2' is 4 cards and so it is also for a '10'

Having this Understanding, let's solve the question properly.

The probability that the FIRST CARD is 2 = 4/52

Probability that the second card without replacement is a 10 = 4 / 51

P( 1st two and 2nd four)

4/52 * 4/51 = 4/663

= 0.0060332

Rounding to 3 decimal places = 0.006

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

idek

step-by-step explanation: