Suppose that a "code" consists of 3 digits, none of which is repeated. (A digit is one of the 10 numbers 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.) How many codes are possible?

There are 720 ways of codes are possible.

Explanation:

Given that the code consists of 3 digits, none of which is repeated.

We need to determine the codes that are possible.

The possible ways of codes can be determined using the permutation formula,

where n is the number of choices and r is the number chosen.

Hence, substituting and , we have,

Simplifying, we get,

Cancelling the common terms, we get,

Multiplying, we get,

Thus, there are 720 ways of codes are possible.

78.59 is the mean

step-by-step explanation:

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.