Suppose that a die is rolled twice. What are the possible values that the following random variables can take on: a. the maximum value to appear in the two rolls; b. the minimum value to appear in the two rolls; c. the sum of the two rolls; d. the value of the first roll minus the value of the second roll

a. A = {1, 2, 3, 4, 5, 6}

b. B = {1, 2, 3, 4, 5, 6}

c. C = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

d. D = {-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5}

Step-by-step explanation:

a. the maximum value to appear in the two rolls

Since only the maximum value is computed, the variable can assume any integer from 1 to 6:

A = {1, 2, 3, 4, 5, 6}

b. the minimum value to appear in the two rolls;

Since only the minimum value is computed, the variable can assume any integer from 1 to 6:

B = {1, 2, 3, 4, 5, 6}

c. the sum of the two rolls;

The minimum value would be from rolling two ones (sum is 2) and the maximum value would be from rolling two sixes (sum is 12). Every integer in-between is possible:

C = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

d. the value of the first roll minus the value of the second roll

The minimum value would be from rolling a one and a six (result is -5) and the maximum value would be from rolling a six and a one (result is 5). Every integer in-between is possible:

D = {-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5}

question is incomplete.

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice