Is (-5,-5) a solution of y>- 2x + 4?

No, (-5, -5) is not a solution

Step-by-step explanation:

Step 1:  Plug in -5 for y and -5 for x

y > -2x + 4

-5 > -2(-5) + 4

-5 > 10 + 4

-5 > 14

 No, (-5, -5) is not a solution

ok then what happened.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15