Pulse rates (in beats per minute) were collected on a sample of 36 men. The five number summary for the data is as follows: Lo: 56 Lower Quartile: 71 Median: 80 Upper Quartile: 100 Hi: 140 How many men had a pulse rate between 56 & 100?

27 men had a pulse rate between 56 & 100.  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 36

Five number summary:

Lowest value: 56

Lower Quartile: 71

Median: 80

Upper Quartile: 100

Highest value: 140

We have to find the number of men that had a pulse rate between 56 & 100.

56 is the lowest value of data and 100 is the third quartile of data.

Now, the third quartile give 75 percentile of data, thus, 75% of data lies between lowest value and the third quartile.

Thus, 75% of men have a pulse rate between 56 & 100.

Number of men that had a pulse rate between 56 & 100 =

Thus, 27 men had a pulse rate between 56 & 100.

the thermometer is precise but not accurate

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3