Arectangle has a length that is 5 inches greater than its width, and its area is 104 square inches. the equation (x + 5)x = 104 represents the situation, where x represents the width of the rectangle.
(x + 5)x = 104
x2 + 5x – 104 = 0
determine the solutions of the equation. what solution makes sense for the situation?
x =
what are the dimensions of the rectangle?
width = inches
length = inches

Keywords:

Rectangle, length, width, area, inches, equation, variable

For this case, we have a ractangle of area 104 square inches, they tell us that its length is 5 inches greater than the width. In addition, we have the following equation where the variable "x" represents the width of the rectangle.

By definition, the area of a rectangle is given by:

Where:

square inches

For the width we have:

We find the solutions of the equation by factoring, that is, we look for two numbers that when multiplied give as result -104 and when summed give as result +5. So, those numbers are +13 and -8.

So, we have:

The roots are:

The solution that makes sense for the width of the rectangle is: x_ {2} = 8

Thus, the width of the rectangle is x = 8 inches

If the thickness is 5 inches greater than the width, then:

Verifying the area, we have:

square inches

ANswer:

triangle and cube

step-by-step explanation: