You have at most $20.75 to spend at a fair. Rides cost $0.50 each, and games cost $2 each. Let r be numbers of rides and g be numbers of games. Write an inequality that represents the numbers of rides and games you can afford.

0.5r + 2g  ≤ 20.75 is the required inequality

Step-by-step explanation:

Step 1 :

Given .

Maximum amount available to spend on rides = $20.75

Cost of each ride = $0.50

Cost of each game = $2

Let r me the number of rides and g be the number of games

We need  to find the inequality that represents the maximum number of games and rides that we can afford

Step 2 :

The cost of r rides = 0.5 × r = 0.5 r

The cost of g games = 2 × g = 2 g

The sum of these costs should be less that the total available amount of $20.75

So we have the inequality

0.5r + 2g  ≤ 20.75

Step 3 :

Answer :

0.5r + 2g  ≤ 20.75 is the required inequality

its adding 5.5 each time

step-by-step explanation: