Which is a factor of 18x2 + 3x − 6?
2x+1
2x+3
3x+2
3x-1

The correct option is C. (3·x + 2)

Step-by-step explanation:

The quadratic equation is given to be : 18·x² + 3·x - 6

We need to find the factors of this given quadratic equation.

Let f(x) = 18·x² + 3·x - 6

⇒ f(x) = 3 × (6·x² + x - 2)

⇒ f(x) = 3 × (6·x² - 3·x + 4·x - 2)

⇒ f(x) = 3 × [3·x(2·x - 1) + 2(2·x - 1)]

⇒ f(x) = 3·(2·x - 1)·(3·x + 2)

Now, from the given options : The required factor of the given quadratic equation is (3·x + 2)

Therefore, The correct option is C. (3·x + 2)

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17