An estate of $686,000 is left to three siblings. The eldest receives 2 times as much as the youngest. The middle sibling receives $15,000 more than the youngest
How much did each receive?
The eldest sibling received ?the middle sibling received ?and the youngest sibling received?

The oldest gets -> $335,500

The middle gets -> $182,750

The youngest gets -> $167,750

Step-by-step explanation:

Step 1:  Make an equation

686,000 = 2y + (15,000 + y) + y

Step 2:  Solve for y

686,000 - 15,000 = 2y + 15,000 + y + y - 15,000

671000 / 4 = 4y / 4

167,750 = y

Step 3:  Figure the amount of money the middle sibling gets

m = y + 15,000

m = 167,750 + 15,000

m = 182,750

Step 4:  Figure the amount of money the oldest sibling gets

o = 2y

o = 2(167,750)

o = 335,500

 The oldest gets -> $335,500

                The middle gets -> $182,750

                The youngest gets -> $167,750

$335,500

$182,750

$167,750

Step-by-step explanation:

Let the amount received by the eldest sibling be A , the middle sibling be B and the youngest sibling be C.

Given

The eldest A received two times as the youngest C.

That’s

A = 2C

Also,the middle sibling received $15000 more than the youngest .

That’s

B = C + $15000

Therefore,

A + B + C = $686000

We now have three expressions

A = 2C

B = C + 15000

A + B + C = 686000

Substitute the first two expressions or values of A and B into the third expression

We have

2C + C + 15000 + C =686000

Rearrange the expression as

2C + C + C + 15000 =

4C + 15000 = 686000

Subtract 15000 from both sides

4C + 15000 - 15000 = 686000 - 15000

4C = 671000

Divide both sides by by 4

C = 671000/4

C = 167750

C = $167,750

The youngest sibling received $167,750

Recall,

A = 2C

Therefore

A = 2 x $167,750

A = $335,500

The eldest sibling received

$335,500

Also,

B = C + $15000

B = $167,750 + $15000

B = $182,750

The middle sibling received $182,750

The eldest sibling received $335,500

The middle sibling received $192,750 and

The youngest sibling received $167,750

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