Find the solution set:
9x^2+4x-5=0
(9x is sqaured [^2])
Separate the two values with a comma

Step-by-step explanation:

9x²+4x-5=0

9x²+9x-5x-5=0

9x(x+1)-5(x+1)=0

(x+1)(9x-5)=0

x=-1,5/9

x = - 1, x =

Step-by-step explanation:

Given

9x² + 4x - 5 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 9 × - 5 = - 45 and sum = + 4

the factors are + 9 and - 5

Use these factors to split the x- term

9x² + 9x - 5x - 5 = 0 ( factor the first/second and third/fourth terms )

9x(x + 1) - 5(x + 1) = 0 ← factor out (x + 1) from each term

(x + 1)(9x - 5) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

9x - 5 = 0 ⇒ 9x = 5 ⇒ x =

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