Use the quadratic formula to solve 2x^2 + 12x = -17. Show your work and explain your steps. If you do not explain or show your work, you will not receive credit.

The answer to your question is            x₁ = -3 +    ;  x₂ = -3

Step-by-step explanation:

Data

                     2x² + 12x = -17

Process

1.- Equal to zero

                   2x² + 12x + 17 = 0

2.- Identify a, b and c

a = 2

b = 12

c = 17

3.- Substitute in the general formula

                   x =

4.- Simplify

                   x =

                   x =

                   x =

5.- Find x1 and x2

                  x₁ = -3 +                        x₂ = -3

Step-by-step explanation:

The given quadratic equation is expressed as

2x² + 12x = - 17

Rearranging the equation so that it will be in the standard form of ax² + bx + c, it becomes

2x² + 12x + 17 = 0

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 2

b = 12

c = 17

Therefore,

x = [- 12 ± √(12² - 4 × 2 × 17)]/2 × 1

x = [- 12 ± √(144- 136)]/2

x = [- 12 ± √8]/2

x = (- 12 + 2.83)/2 or x = (- 12 - 2.83)/2

x = 4.5 or x = 7.415

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.

sure i'm up for it

step-by-step explanation: