A TV remote control has keys for channels 0 through 9.

a) If a key is selected at random, what is the probability that the key for channel 8 is pressed?

b) If a key is selected at random, what is the probability that the key for an even number is pressed?

11.1 #12

c) If a key is selected at random, what is the probability that the key for a number more than 6 is pressed?

a) 0.1

b) 0.5

c) 0.3

Step-by-step explanation:

A TV remote control has keys for channels 0 through 9.

So, the total possible outcomes = 10

a) If a key is selected at random, what is the probability that the key for channel 8 is pressed?

the possible outcome of 8 = 1

P(8) = (the possible outcome of 8)/(total outcomes) = 1/10 = 0.1

b) If a key is selected at random, what is the probability that the key for an even number is pressed?

The even numbers are = 0 , 2 , 4 , 6 , 8

the possible outcome of even number = 5

P(even number) = 5/10 = 1/2 = 0.5

c) If a key is selected at random, what is the probability that the key for a number more than 6 is pressed?

The numbers more than 6 are = 7 , 8 , 9

the possible outcome of more than 6 = 3

P(numbers more than 6) = 3/10 = 0.3

28

step-by-step explanation:

8+8+6+6

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement