Write the statement for the problem in mathematical language. Use x for the tens digit and y for the unit digits in the two digit numbers.
a) Find the two-digit number which is 2 times the sum of its digits
b) Find the two-digit number which is greater than the product of its digits by 26

Part a) The number is 18

Part b)  The number is 32

Step-by-step explanation:

Let

x ----> tens digit

y ---> unit digits

N ----> the number (xy)

Part a) Find the two-digit number which is 2 times the sum of its digits

we know that

The number is equal to

----> equation A

Remember that

The two-digit number is 2 times the sum of its digits

so

-----> equation B

equate equation A and equation B

The only single-digit values for x and y that satisfy the requirements are

x=1, y=8

therefore

The number is 18

Part b) Find the two-digit number which is greater than the product of its digits by 26

we know that

The number is equal to

----> equation A

Remember that

The two-digit number is greater than the product of its digits by 26

so

-----> equation B

equate equation A and equation B

Subtract xy from each side

Factor -y

X must be bigger than 2 or we cannot get 26

Let x=3

Subtract 30 from each side

Divide by -2  both sides

therefore

The number is 32

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!