The graph of the function f(x)=ax^2+bx+c has its vertex at (0,1) and passes through the point (1,9) find a b and c

The equation of a parabola is , where (h,k) represents the vertex.

The values of a, b and c are 8, 0 and 1, respectively.

We have:

--- the vertex

--- the point it passes through

Substitute in

Substitute in

Collect like terms

Substitute in

So, the equation of the parabola is:

Compare to

See attachment for the equation of

Read more about equations of parabola at:

link

Step-by-step explanation:

The vertex form of a quadratic is where the vertex is .

We are given .

Plugging this in gives us:

Simplifying:

Since it passes through , we can use this information to find .

So the quadratic in vertex form is .

That happens to be in standard form as well.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

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step-by-step explanation: