The length of a rectangular shipping pallet is 3 feet less than 3 times its width. Its area is 18 square feet. Find the dimensions of the pallet . Find the dimensions of the pallet

length = 6 feet

Width = 3 feet

Step-by-step explanation:

Let L represent the length of the pallet.

Let W represent the width of the pallet.

The shipping pallet is rectangular.

The length of a rectangular shipping pallet is 3 feet less than 3 times its width. This is expressed as

L = 3W - 3

The formula for determining the area of a rectangle is expressed as

Area = LW

Its area is 18 square feet. This is expressed as

LW = 18- - - - - - - -- - - - 1

Substituting L = 3W - 3 into equation 1, it becomes

W(3W - 3) = 18

3W² - 3W - 18 = 0

Dividing through by 3, it becomes

W² - W - 6 = 0

W² + 2W - 3W - 6 = 0

W(W + 2) - 3(W + 2) = 0

W - 3 = 0 or W + 2 = 0

W = 3 or W = - 2

Since the width cannot be negative, then W = 3

L = 3W - 3 = 3 × 3 - 3

L = 9 - 3 = 6

the 4th choice is the correct one

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)